Integrand size = 24, antiderivative size = 79 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=-\frac {41503}{160} (1-2 x)^{5/2}+\frac {13013}{32} (1-2 x)^{7/2}-\frac {39977}{144} (1-2 x)^{9/2}+\frac {17541}{176} (1-2 x)^{11/2}-\frac {7695}{416} (1-2 x)^{13/2}+\frac {45}{32} (1-2 x)^{15/2} \]
-41503/160*(1-2*x)^(5/2)+13013/32*(1-2*x)^(7/2)-39977/144*(1-2*x)^(9/2)+17 541/176*(1-2*x)^(11/2)-7695/416*(1-2*x)^(13/2)+45/32*(1-2*x)^(15/2)
Time = 0.02 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.48 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=-\frac {(1-2 x)^{5/2} \left (307478+1074070 x+1944575 x^2+2045655 x^3+1180575 x^4+289575 x^5\right )}{6435} \]
-1/6435*((1 - 2*x)^(5/2)*(307478 + 1074070*x + 1944575*x^2 + 2045655*x^3 + 1180575*x^4 + 289575*x^5))
Time = 0.19 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {99, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (1-2 x)^{3/2} (3 x+2)^3 (5 x+3)^2 \, dx\) |
\(\Big \downarrow \) 99 |
\(\displaystyle \int \left (-\frac {675}{32} (1-2 x)^{13/2}+\frac {7695}{32} (1-2 x)^{11/2}-\frac {17541}{16} (1-2 x)^{9/2}+\frac {39977}{16} (1-2 x)^{7/2}-\frac {91091}{32} (1-2 x)^{5/2}+\frac {41503}{32} (1-2 x)^{3/2}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {45}{32} (1-2 x)^{15/2}-\frac {7695}{416} (1-2 x)^{13/2}+\frac {17541}{176} (1-2 x)^{11/2}-\frac {39977}{144} (1-2 x)^{9/2}+\frac {13013}{32} (1-2 x)^{7/2}-\frac {41503}{160} (1-2 x)^{5/2}\) |
(-41503*(1 - 2*x)^(5/2))/160 + (13013*(1 - 2*x)^(7/2))/32 - (39977*(1 - 2* x)^(9/2))/144 + (17541*(1 - 2*x)^(11/2))/176 - (7695*(1 - 2*x)^(13/2))/416 + (45*(1 - 2*x)^(15/2))/32
3.19.71.3.1 Defintions of rubi rules used
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) )^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | | (GtQ[m, 0] && GeQ[n, -1]))
Time = 0.97 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.44
method | result | size |
gosper | \(-\frac {\left (1-2 x \right )^{\frac {5}{2}} \left (289575 x^{5}+1180575 x^{4}+2045655 x^{3}+1944575 x^{2}+1074070 x +307478\right )}{6435}\) | \(35\) |
trager | \(\left (-180 x^{7}-\frac {7200}{13} x^{6}-\frac {83331}{143} x^{5}-\frac {155251}{1287} x^{4}+\frac {287273}{1287} x^{3}+\frac {373931}{2145} x^{2}+\frac {155842}{6435} x -\frac {307478}{6435}\right ) \sqrt {1-2 x}\) | \(44\) |
pseudoelliptic | \(-\frac {\left (1158300 x^{7}+3564000 x^{6}+3749895 x^{5}+776255 x^{4}-1436365 x^{3}-1121793 x^{2}-155842 x +307478\right ) \sqrt {1-2 x}}{6435}\) | \(45\) |
risch | \(\frac {\left (1158300 x^{7}+3564000 x^{6}+3749895 x^{5}+776255 x^{4}-1436365 x^{3}-1121793 x^{2}-155842 x +307478\right ) \left (-1+2 x \right )}{6435 \sqrt {1-2 x}}\) | \(50\) |
derivativedivides | \(-\frac {41503 \left (1-2 x \right )^{\frac {5}{2}}}{160}+\frac {13013 \left (1-2 x \right )^{\frac {7}{2}}}{32}-\frac {39977 \left (1-2 x \right )^{\frac {9}{2}}}{144}+\frac {17541 \left (1-2 x \right )^{\frac {11}{2}}}{176}-\frac {7695 \left (1-2 x \right )^{\frac {13}{2}}}{416}+\frac {45 \left (1-2 x \right )^{\frac {15}{2}}}{32}\) | \(56\) |
default | \(-\frac {41503 \left (1-2 x \right )^{\frac {5}{2}}}{160}+\frac {13013 \left (1-2 x \right )^{\frac {7}{2}}}{32}-\frac {39977 \left (1-2 x \right )^{\frac {9}{2}}}{144}+\frac {17541 \left (1-2 x \right )^{\frac {11}{2}}}{176}-\frac {7695 \left (1-2 x \right )^{\frac {13}{2}}}{416}+\frac {45 \left (1-2 x \right )^{\frac {15}{2}}}{32}\) | \(56\) |
meijerg | \(-\frac {27 \left (-\frac {8 \sqrt {\pi }}{15}+\frac {4 \sqrt {\pi }\, \left (8 x^{2}-8 x +2\right ) \sqrt {1-2 x}}{15}\right )}{\sqrt {\pi }}+\frac {\frac {564 \sqrt {\pi }}{35}-\frac {141 \sqrt {\pi }\, \left (160 x^{3}-128 x^{2}+8 x +8\right ) \sqrt {1-2 x}}{70}}{\sqrt {\pi }}-\frac {2649 \left (-\frac {64 \sqrt {\pi }}{945}+\frac {4 \sqrt {\pi }\, \left (1120 x^{4}-800 x^{3}+24 x^{2}+16 x +16\right ) \sqrt {1-2 x}}{945}\right )}{16 \sqrt {\pi }}+\frac {\frac {1842 \sqrt {\pi }}{385}-\frac {921 \sqrt {\pi }\, \left (26880 x^{5}-17920 x^{4}+320 x^{3}+192 x^{2}+128 x +128\right ) \sqrt {1-2 x}}{24640}}{\sqrt {\pi }}-\frac {405 \left (-\frac {1024 \sqrt {\pi }}{45045}+\frac {4 \sqrt {\pi }\, \left (147840 x^{6}-94080 x^{5}+1120 x^{4}+640 x^{3}+384 x^{2}+256 x +256\right ) \sqrt {1-2 x}}{45045}\right )}{8 \sqrt {\pi }}+\frac {\frac {120 \sqrt {\pi }}{1001}-\frac {15 \sqrt {\pi }\, \left (1537536 x^{7}-946176 x^{6}+8064 x^{5}+4480 x^{4}+2560 x^{3}+1536 x^{2}+1024 x +1024\right ) \sqrt {1-2 x}}{128128}}{\sqrt {\pi }}\) | \(275\) |
Time = 0.22 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.56 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=-\frac {1}{6435} \, {\left (1158300 \, x^{7} + 3564000 \, x^{6} + 3749895 \, x^{5} + 776255 \, x^{4} - 1436365 \, x^{3} - 1121793 \, x^{2} - 155842 \, x + 307478\right )} \sqrt {-2 \, x + 1} \]
-1/6435*(1158300*x^7 + 3564000*x^6 + 3749895*x^5 + 776255*x^4 - 1436365*x^ 3 - 1121793*x^2 - 155842*x + 307478)*sqrt(-2*x + 1)
Time = 0.78 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.89 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=\frac {45 \left (1 - 2 x\right )^{\frac {15}{2}}}{32} - \frac {7695 \left (1 - 2 x\right )^{\frac {13}{2}}}{416} + \frac {17541 \left (1 - 2 x\right )^{\frac {11}{2}}}{176} - \frac {39977 \left (1 - 2 x\right )^{\frac {9}{2}}}{144} + \frac {13013 \left (1 - 2 x\right )^{\frac {7}{2}}}{32} - \frac {41503 \left (1 - 2 x\right )^{\frac {5}{2}}}{160} \]
45*(1 - 2*x)**(15/2)/32 - 7695*(1 - 2*x)**(13/2)/416 + 17541*(1 - 2*x)**(1 1/2)/176 - 39977*(1 - 2*x)**(9/2)/144 + 13013*(1 - 2*x)**(7/2)/32 - 41503* (1 - 2*x)**(5/2)/160
Time = 0.18 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.70 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=\frac {45}{32} \, {\left (-2 \, x + 1\right )}^{\frac {15}{2}} - \frac {7695}{416} \, {\left (-2 \, x + 1\right )}^{\frac {13}{2}} + \frac {17541}{176} \, {\left (-2 \, x + 1\right )}^{\frac {11}{2}} - \frac {39977}{144} \, {\left (-2 \, x + 1\right )}^{\frac {9}{2}} + \frac {13013}{32} \, {\left (-2 \, x + 1\right )}^{\frac {7}{2}} - \frac {41503}{160} \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} \]
45/32*(-2*x + 1)^(15/2) - 7695/416*(-2*x + 1)^(13/2) + 17541/176*(-2*x + 1 )^(11/2) - 39977/144*(-2*x + 1)^(9/2) + 13013/32*(-2*x + 1)^(7/2) - 41503/ 160*(-2*x + 1)^(5/2)
Time = 0.27 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.23 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=-\frac {45}{32} \, {\left (2 \, x - 1\right )}^{7} \sqrt {-2 \, x + 1} - \frac {7695}{416} \, {\left (2 \, x - 1\right )}^{6} \sqrt {-2 \, x + 1} - \frac {17541}{176} \, {\left (2 \, x - 1\right )}^{5} \sqrt {-2 \, x + 1} - \frac {39977}{144} \, {\left (2 \, x - 1\right )}^{4} \sqrt {-2 \, x + 1} - \frac {13013}{32} \, {\left (2 \, x - 1\right )}^{3} \sqrt {-2 \, x + 1} - \frac {41503}{160} \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} \]
-45/32*(2*x - 1)^7*sqrt(-2*x + 1) - 7695/416*(2*x - 1)^6*sqrt(-2*x + 1) - 17541/176*(2*x - 1)^5*sqrt(-2*x + 1) - 39977/144*(2*x - 1)^4*sqrt(-2*x + 1 ) - 13013/32*(2*x - 1)^3*sqrt(-2*x + 1) - 41503/160*(2*x - 1)^2*sqrt(-2*x + 1)
Time = 0.03 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.70 \[ \int (1-2 x)^{3/2} (2+3 x)^3 (3+5 x)^2 \, dx=\frac {13013\,{\left (1-2\,x\right )}^{7/2}}{32}-\frac {41503\,{\left (1-2\,x\right )}^{5/2}}{160}-\frac {39977\,{\left (1-2\,x\right )}^{9/2}}{144}+\frac {17541\,{\left (1-2\,x\right )}^{11/2}}{176}-\frac {7695\,{\left (1-2\,x\right )}^{13/2}}{416}+\frac {45\,{\left (1-2\,x\right )}^{15/2}}{32} \]